[ANSI-Smalltalk] Agenda items...

[Paolo Bonzini]

> Hmmm... well, but even then, we have that the integer 2^emax is a 
> double, but 2^(emax + 1) is not a double.  Is perhaps the convenience of 
> coincidence the confusing part here?  I didn't mean to write such 
> amounts in any particular mantissa notation.

Yes, most likely.  I interpreted 2^emax as "1*2^emax" which is not LIA 
because the mantissa is 1.

Paolo